?
4̿
x/3 + (2x-3)/9 + (2x+6)/27
= 9x/27 + (6x-9)/27 + (2x+6)/27
= (17x-3)/27
ι° ư 2x/9 ƴѰ?
ó ü x
ù° A 1/3,
2x/3
⼭ 1/3 .. 2x/9 ƴ?
1̳ϱ.
1 3 ž
ߵƴѰ
ʵб?
ó x/3
ι° (2x/3-1)/3 = (2x/3-3/3)/3 = (2x-3)/3/3 = (2x-3) / 9
((2x-3) / 9+1)/3=
((2x-3) / 9 +9/9)/3 = ((2x+6) / 9)/3=(2x+6)/27
1. ü 1/3̴ x/3
2. 2x/3. γ 1̳,
̹ ѷ 2x/3-1̰ װ 3γ, 2x-3/9
3. 2 Ѹ ݳϸ 2x-3/9̰,
1ϸ 2x+6/9 װ 3γ (2x+6)/27
ʵε ĺ ȣ ǥϰ
Ǫ??
4̿